NEB 2023 Physics Thermodynamics one shot notes


Thermodynamics System  

A Certain region in the space used to study the thermodynamic process is called a thermodynamics system. There are three types of thermodynamics Systems.

a) Open system

 The system which exchanges heat or matter is called an open system.

b) Closed System 

 The System which exchanges heat only is called a closed system.

c) Isolated System 

The System which exchanges neither heat and not matter is Called the Isolated system.


Thermodynamics Process

1) Isothermal Process

The process in which temperature remains constant is called the isothermal process.

We have, 
 PV = nRT 
for isothermal process PV = constant 

2) Isochoric process

The Process in which volume remains constant is called isochoric constant.

3) Isobaric process

The process in which pressure remains constant is called the isobaric process.

4) Adiabatic process

The process in which pressure, volume, and temperature change but the amount of heat remain constant is called the adiabatic process.


Work done by expansion

Fig: Work done by expansion

 Fig: Work done by expansion 


Let us consider a gas kept inside a cylinder provided with a movable and frictionless piston at pressure 'p', volume 'v', and temperature 'T'. Suppose the gas expands by a small volume 'dv' and the piston moved forward by distance  'dx'. If A is the cross-sectional area of the cylinder then force on the piston,

F = P.A       [ P=F/A]

Also, the change in volume

 dv = Adx

Now, 

Small work done,
dw= F.dx
dw= PAdx
dw= Pdv
which is external work done


PV diagram

The variation of pressure and volume in a thermodynamics process represented by the diagram is called the PV diagram. 
 
PV diagram

Area of KLJO = OJ x KO
= Pdv
= work done

Therefore, the area of the PV diagram gives the work done during the thermodynamics process. 


Internal energy

In the case of real gases, the molecules are attached to each other by intermolecular force and molecules are in motion. So, real gas molecules exhibit both potential energy and kinetic energy. Therefore, the sum of kinetic energy and potential energy is called internal energy. 

In the case of an ideal gas, there is no P.E. so in the case of ideal gas internal energy is K.E. only and depends upon absolute temperature.   

∴ Internal energy = kinetic energy + potential energy  

For Ideal gas, Internal energy = kinetic energy


First Law of thermodynamics

It states that if a certain amount of heat is supplied to the given system then a part of the heat may be used to increase the internal energy and the remaining part is used for work done.

If dQ is the amount of heat supplied to the system and du, dw is the increases in internal energy and external work done respectively, then according to the first law of thermodynamics.

dQ = du + dw --- (i)

since 

dQ = du + pdv

If dv = 0 then dw = 0

∴ dQ = du

It means the total amount of heat supplied is used to increase external work done only when the volume is constant.


Heat Capacity of gas

Molar heat as constant volume (Cv) 

It is defined as the amount of heat required to rise the temperature of 1 mole of gas through 1 kelvin at constant volume. It is denoted by Cv.

Molar heat as constant pressure (Cp)

It is defined as the amount of heat required to rise the temperature of 1 mole of gas through 1 kelvin at constant pressure. It is denoted by Cp.


Mayer's formula (Cp-Cv=R)

Fig: Gas in cylinder
Fig: Gas in a cylinder

Let us consider 'n' mole of gas kept in a cylinder provided with the movable and frictionless piston at pressure 'P', volume 'V', and Temperature 'T'. Suppose the gas is heated at constant volume initially and dQ is the amount of heat given to the system to increase its temperature by dT then,

dQ = nCvdT --- (i)

From the first law of thermodynamics,

dQ = du + PdV 

Since, at constant volume, dv=0

 so, dQ = du

 ∴ du = nCv dT --- (ii)

 Again the gas is heated at constant pressure and dQ be the amount of heat given to the system to increase the temperature by dT.

dQ = nCpdT --- (iii)

 Again from first law of thermodynamics

 dQ = du + Pdv

 nCpdT = nCvdT + Pdv---(iv) ∴using equation (ii) 

 From idea gas equation

 PV = nRT

 Differentiating both sides with respect to at T at constant pressure.

Class 12 Physics First law of thermodynamics notes

Pdv = nRdT --- (v)

using eqn (v) in eqn (iv)

nCpdT = nCvdT + nRdT 

Cp = Cv+R 

Cp - Cv = R

Which is mayers formula


Equation of Adiabatic Process

From the first law of thermodynamics

dQ = du + pdv --- (i)

For adiabatic process

dQ = 0 (∴ heat constant)

du + Pdv = 0 --- (ii)

If Cv is the molar heat capacity at a constant volume for one mole of gas,

du = 1Cvdt --- (iii)

using equation (iii) in equation (ii)

CvdT +  Pdv = 0 --- (iv)

Also ideal gas equation for 1 mole of gas

PV = RT

Differentiating both sides with respect to 'T'

P dv / dT + V dP / dT = R dT / dT

P dv + vdP = R dT

dT = Pdv + Vdp / R --- (v)

using equation (v) in equation (iv)

Cv ( Pdv + Vdp / R ) + Pdv = 0

 Cv (Pdv + Vdp) + RPdv = 0

(CV+R) Pdv + CvVdp = 0   [ ∴ cp-cv=R]

CpPdv + CvVdp = 0 

Dividing both side by CvPv

Class 12 Physics First law of thermodynamics Notes

Integrating on both sides 

Which is an adiabatic equation in terms of pressure and volume.

In terms of pressure and volume

Class 12 Physics First law of thermodynamics notes




In terms of temperature and volume

We have, 

PV=RT




Then equation (vi) becomes




In terms of pressure and temperature

We have,











Work done by an isothermal process 

Class 12 Physics First law of thermodynamics notes

Let us consider that 1 mole of gas is kept in a cylinder provided with a movable and frictionless piston. Also, let P1, V1, and T be the initial pressure, volume, and temperature respectively. By keeping the temperature constant volume can be changed to V2. So that pressure also changed to P2. So, that small work is done.

dw = PdV --- (i)

Thus total work done

Class 12 Physics First law of thermodynamics notes






for 1 mole of the gas ideal gas equation be,

PV = RT

P = RT / V --- (iii)

using equation (iii) in equation (ii)

Class 12 Physics First law of thermodynamics notes







 





Also from an isothermal process



Equations (iv) and (v) are required expressions for the isothermal process when gas is 1 mole




Work done by Adiabatic process 

Let us consider that 1 mole of gas is kept in a cylinder provided with a movable and frictionless piston. Also, Consider the gas expansion adiabatically from initial volume ‘V1’ to find volume ‘V2’.The work done is given by. 














using equation (ii) in (i)
Class 12 Physics First law of thermodynamics notes













For one mole of gas 

Class 12 Physics First law of thermodynamics notes

∴ PV=RT
 



Equations (iv) and (iii) are required expressions for n mole of gas during the adiabatic Process.


Reversible and Irreversible Process

The process which returns to the initial state from the final state exactly along the same path is called the reversible process. The net work done during the reversible process is O.

PV diagram for a reversible process

Fig: PV diagram for a reversible process

The process which doesn't return to the initial state from the final state exactly along the same path is called an irreversible process. The net work done during the irreversible process is net zero.


PV diagram for an irreversible process

Fig: PV diagram for an irreversible process



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Second Law Of Thermodynamics

1) Kelin's Statements

It is impossible to get a continuous supply of work from a body by cooling it to a temperature lower than that of its surroundings.

2) Clausius Statements

It is impossible to make flow to heat from the body at a lower temperature to the body at a higher temperature without any external work done.

Heat Engine

A heat engine is a device that converts heat energy into mechanical work. It consisted of three parts they are:-

1) Source

The source is a hot body at a constant high temperature from which the heat engine can draw heat.

2) Working Substance

Working Substance is an ideal gas that on being supplied with heat performs mechanical work.

3) Sink

A sink is a cold body at a low temperature to which any amount of heat is rejected.

The efficiency of Heat Engine

Heat engine

Fig: Heat engine

The efficiency of a heat engine is defined as the ratio of the amount of work done to the total heat taken from the source.


Class 12 Physics Second law of thermodynamics Notes

If, Q1 is the amount of heat taken from the source and Q2 is the heat rejected to sink.
Then work done (Q) = Q1 - Q2

Class 12 Physics Second law of thermodynamics Notes

No engine will convert all the heat absorbed from the source into work. So, the efficiency of an engine is always less than 1 or 100%.

Refrigerator

A refrigerator is a device that transfers heat from a cold body to a heat body by means of an external agency.

Block diagram of refrigerator
Fig: Block diagram of refrigerator

Let Q be the amount of heat taken from the body at a lower temperature and W be the work done on it. So, that amount of heat absorbed by the hot body is, 

Class 12 Physics Second law of thermodynamics Notes

Co-Efficient of Performance of a Refrigerator


The coefficient of performance of a refrigerator is defined as the ratio of the amount of heat transfer from a cold body to a hot body to the amount of work done on it.
Class 12 Physics Second law of thermodynamics Notes

Relation between co-efficient of performance and efficiency

for a heat engine working between Q1 and Q2 is,


Class 12 Physics Second law of thermodynamics Notes

and for refrigerator working between Q1 and Q2 is,

Class 12 Physics Second law of thermodynamics Notes

From equation (i)

Class 12 Physics Second law of thermodynamics Notes

using equation (iii) in Equation (ii)

Class 12 Physics Second law of thermodynamics Notes

This is a required relationship between the coefficient of performance and efficiency.

Carnot engine

Carnot performs an ideal heat engine having maximum efficiency which can work in a cycle of operation is called Carnot engine.

Carnot cycle

The Carnot engine performs work in four-cycle of operations having two isothermal and two adiabatic processes such a cycle of operation is called the Carnot cycle.

Consider a mole of an ideal gas enclosed in a cylinder having initial pressure, volume, and temperature P1, V1, and T1 respectively. The point corresponding to this pressure, volume and temperature are A in the PV diagram as shown in the figure. The different processes in a Carnot cycle are discussed below.  

PV - diagram of the Carnot cycle

Fig: PV - diagram of the Carnot cycle

(I) Isothermal expansion

Initially, the cylinder is placed on a hot source, and gas absorbed a Q1 amount of heat at a constant temperature, and gas is expanded isothermally from initial state A(P1, V1) to final state B(V1, V2) which is represented by curve AB in a PV-diagram.

Class 12 Physics Second law of thermodynamics Notes

(II) Adiabatic expansion

Now, the cylinder is kept on an insulating stand, and gas is expanded adiabatically from the initial state is B(P2, V2) to C(P3, V3), and temperature changes from T 1 to T2 which is shown by curve BC in PV-diagram.

Class 12 Physics Second law of thermodynamics Notes

(III) Isothermal compression

Now, the engine is placed on a sink and is compressed isothermally from initial state C(P3, V3) to D(P4, V4) at constant temperature T2 which is shown by curve CD in PV-diagram. At this stage, an amount of heat is rejected to sink. 

Class 12 Physics Second law of thermodynamics Notes

Adiabatic compression

Now, the cylinder is kept on an insulating stand and compressed the gas adiabatically from D(P4, V4) to A(P1, V1) which is shown by curve DA in PV-diagram and temperature change from T2 toT1.

Class 12 Physics Second law of thermodynamics Notes

Therefore the total amount of work done during one complete cycle; is,

Class 12 Physics Second law of thermodynamics Notes

Hence in the Carnot engine, net work done by the gas per cycle is numerically equal to the total area of the loop ABCDA representing the cycle.

The efficiency of the Carnot cycle 

It is defined as the radius of external work done (w) by the engine to the amount of heat energy (Q1) absorbed from the heat source.

Class 12 Physics Second law of thermodynamics Notes

Class 12 Physics Second law of thermodynamics Notes

From the adiabatic curve BC

Class 12 Physics Second law of thermodynamics Notes

Again from the adiabatic curve DA

Class 12 Physics Second law of thermodynamics Notes

From equations (vi) and (vii)

Class 12 Physics Second law of thermodynamics Notes

using equation (viii) in equation (v) , we get 

Class 12 Physics Second law of thermodynamics Notes

This is a required expression for the efficiency of the Carnot engine

Petrol engine 

A Petrol engine is developed by otto which consists of a cylinder fitted with a moveable piston. There are two holes in the cylinder fitted with inlet value ( I ) and outlet value ( v ). The opening and closing of those values are controlled by the motion of the piston. A spark plug 'S' produces a spark that ignites the mixture of air and Petrol (98-1. air and 2.). Petrol). The Piston is attached to the rod R which is connected to the wheels of vehicles. The Petrol engine works in the following four steps.

Four-stroke of a petrol engine

Fig: Four-stroke of a petrol engine

PV diagram of a petrol engine

Fig:- PV diagram of a petrol engine

I. Suction Stroke:

It is shown in figure (a). In this Stroke the inlet valve 'I' opens and a mixture of oil and petrol is sucked into the cylinder by the outward motion of the piston which is shown by curve EA.

II. Compression Stroke:

It is shown in figure (b). In this stroke the inlet and outlet valve are closed. The mixture of air and petrol is compressed adiabatically 1/5 of original volume hence the temperature rise up to 600 ℃ which is shown by curve AB in PV diagram.

III. Working Stroke:

It is shown in figure (c). In this stroke, both the inlet and outlet valve are closed and a spark is produced from the spark plug 's' hence the temperature rises about 200 ℃ and hence pressure also rises up to 15 atmospheres which are shown by curve BC in the PV diagram and in this stage Q1 amount of heat is supplied. After ignition, the piston is pushed outward so the wheels rotate due to which temperature and pressure fall down which is shown by curve CD.

IV. Exhaust Stroke:

It is shown in figure (d). In this stroke, the outlet valve 'O' opens hence the burn gas escape out and the pressure falls which is shown by curve DA in the PV diagram.

Efficiency

Class 12 Physics Second law of thermodynamics Notes
Class 12 Physics Second law of thermodynamics Notes

Diesel engine

The diesel engine is developed by Rudolf Diesel and consists of a cylinder fitted with an inlet valve (I), outlet valve (E), and oil spray (O). The piston of the diesel engine is connected to the wheel through the rod 'R'. The working of the diesel engine was completed in 4 steps.

Four-stroke of a diesel engine

Fig:- Four-stroke of a diesel engine  

PV diagram for diesel engine 
  Fig:- PV diagram for diesel engine

I. Suction stroke

It is shown in figure (a) In this stroke inlet; the valve is open and air enters inside the cylinder by the outward movement of the piston. This is shown by Curve CA in the PV diagram.

II. Compression stroke 

It is shown in figure (b) In this stroke. all the values are closed and the air is compressed adiabatically 1/17th of its original volume and the temperature inside the cylinder rises up to 100℃ which is shown by curve AB in the PV diagram.

III. Working Stroke

It is shown in figure (c). In this stroke, the oil spray valve 'O' opens and diesel enters inside the chamber where diesel burns and the volume rises at constant pressure which is shown by curve BC in PV-diagram. The work is done in this stroke. when the temperature inside the chamber reaches 2000°C; and the value O is closed. Now the volume increases due to high temperature and low pressure which is shown by the curve CD in the PV diagram.

IV. Exhaust Stroke

It is shown in figure (d). In this Stroke pressure decreases at constant volume hence a burning gas will escape out from the outlet valve which is shown by curve DA in PV-diagram and the next cycle begins.

Efficiency

Class 12 Physics Second law of thermodynamics Notes
Class 12 Physics Second law of thermodynamics Notes

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